3.2.21 \(\int (d+e x^2)^3 (a+c x^4) \, dx\) [121]

Optimal. Leaf size=79 \[ a d^3 x+a d^2 e x^3+\frac {1}{5} d \left (c d^2+3 a e^2\right ) x^5+\frac {1}{7} e \left (3 c d^2+a e^2\right ) x^7+\frac {1}{3} c d e^2 x^9+\frac {1}{11} c e^3 x^{11} \]

[Out]

a*d^3*x+a*d^2*e*x^3+1/5*d*(3*a*e^2+c*d^2)*x^5+1/7*e*(a*e^2+3*c*d^2)*x^7+1/3*c*d*e^2*x^9+1/11*c*e^3*x^11

________________________________________________________________________________________

Rubi [A]
time = 0.04, antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {1168} \begin {gather*} \frac {1}{7} e x^7 \left (a e^2+3 c d^2\right )+\frac {1}{5} d x^5 \left (3 a e^2+c d^2\right )+a d^3 x+a d^2 e x^3+\frac {1}{3} c d e^2 x^9+\frac {1}{11} c e^3 x^{11} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + e*x^2)^3*(a + c*x^4),x]

[Out]

a*d^3*x + a*d^2*e*x^3 + (d*(c*d^2 + 3*a*e^2)*x^5)/5 + (e*(3*c*d^2 + a*e^2)*x^7)/7 + (c*d*e^2*x^9)/3 + (c*e^3*x
^11)/11

Rule 1168

Int[((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x^2)^q*(a
 + c*x^4)^p, x], x] /; FreeQ[{a, c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && IGtQ[p, 0] && IGtQ[q, -2]

Rubi steps

\begin {align*} \int \left (d+e x^2\right )^3 \left (a+c x^4\right ) \, dx &=\int \left (a d^3+3 a d^2 e x^2+d \left (c d^2+3 a e^2\right ) x^4+e \left (3 c d^2+a e^2\right ) x^6+3 c d e^2 x^8+c e^3 x^{10}\right ) \, dx\\ &=a d^3 x+a d^2 e x^3+\frac {1}{5} d \left (c d^2+3 a e^2\right ) x^5+\frac {1}{7} e \left (3 c d^2+a e^2\right ) x^7+\frac {1}{3} c d e^2 x^9+\frac {1}{11} c e^3 x^{11}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.01, size = 79, normalized size = 1.00 \begin {gather*} a d^3 x+a d^2 e x^3+\frac {1}{5} d \left (c d^2+3 a e^2\right ) x^5+\frac {1}{7} e \left (3 c d^2+a e^2\right ) x^7+\frac {1}{3} c d e^2 x^9+\frac {1}{11} c e^3 x^{11} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x^2)^3*(a + c*x^4),x]

[Out]

a*d^3*x + a*d^2*e*x^3 + (d*(c*d^2 + 3*a*e^2)*x^5)/5 + (e*(3*c*d^2 + a*e^2)*x^7)/7 + (c*d*e^2*x^9)/3 + (c*e^3*x
^11)/11

________________________________________________________________________________________

Maple [A]
time = 0.15, size = 72, normalized size = 0.91

method result size
default \(\frac {c \,e^{3} x^{11}}{11}+\frac {c d \,e^{2} x^{9}}{3}+\frac {\left (a \,e^{3}+3 c \,d^{2} e \right ) x^{7}}{7}+\frac {\left (3 d \,e^{2} a +c \,d^{3}\right ) x^{5}}{5}+a \,d^{2} e \,x^{3}+a \,d^{3} x\) \(72\)
norman \(\frac {c \,e^{3} x^{11}}{11}+\frac {c d \,e^{2} x^{9}}{3}+\left (\frac {1}{7} a \,e^{3}+\frac {3}{7} c \,d^{2} e \right ) x^{7}+\left (\frac {3}{5} d \,e^{2} a +\frac {1}{5} c \,d^{3}\right ) x^{5}+a \,d^{2} e \,x^{3}+a \,d^{3} x\) \(72\)
gosper \(\frac {1}{11} c \,e^{3} x^{11}+\frac {1}{3} c d \,e^{2} x^{9}+\frac {1}{7} x^{7} a \,e^{3}+\frac {3}{7} x^{7} c \,d^{2} e +\frac {3}{5} x^{5} d \,e^{2} a +\frac {1}{5} x^{5} c \,d^{3}+a \,d^{2} e \,x^{3}+a \,d^{3} x\) \(74\)
risch \(\frac {1}{11} c \,e^{3} x^{11}+\frac {1}{3} c d \,e^{2} x^{9}+\frac {1}{7} x^{7} a \,e^{3}+\frac {3}{7} x^{7} c \,d^{2} e +\frac {3}{5} x^{5} d \,e^{2} a +\frac {1}{5} x^{5} c \,d^{3}+a \,d^{2} e \,x^{3}+a \,d^{3} x\) \(74\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x^2+d)^3*(c*x^4+a),x,method=_RETURNVERBOSE)

[Out]

1/11*c*e^3*x^11+1/3*c*d*e^2*x^9+1/7*(a*e^3+3*c*d^2*e)*x^7+1/5*(3*a*d*e^2+c*d^3)*x^5+a*d^2*e*x^3+a*d^3*x

________________________________________________________________________________________

Maxima [A]
time = 0.28, size = 69, normalized size = 0.87 \begin {gather*} \frac {1}{11} \, c x^{11} e^{3} + \frac {1}{3} \, c d x^{9} e^{2} + \frac {1}{7} \, {\left (3 \, c d^{2} e + a e^{3}\right )} x^{7} + a d^{2} x^{3} e + \frac {1}{5} \, {\left (c d^{3} + 3 \, a d e^{2}\right )} x^{5} + a d^{3} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^3*(c*x^4+a),x, algorithm="maxima")

[Out]

1/11*c*x^11*e^3 + 1/3*c*d*x^9*e^2 + 1/7*(3*c*d^2*e + a*e^3)*x^7 + a*d^2*x^3*e + 1/5*(c*d^3 + 3*a*d*e^2)*x^5 +
a*d^3*x

________________________________________________________________________________________

Fricas [A]
time = 0.31, size = 75, normalized size = 0.95 \begin {gather*} \frac {1}{5} \, c d^{3} x^{5} + a d^{3} x + \frac {1}{77} \, {\left (7 \, c x^{11} + 11 \, a x^{7}\right )} e^{3} + \frac {1}{15} \, {\left (5 \, c d x^{9} + 9 \, a d x^{5}\right )} e^{2} + \frac {1}{7} \, {\left (3 \, c d^{2} x^{7} + 7 \, a d^{2} x^{3}\right )} e \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^3*(c*x^4+a),x, algorithm="fricas")

[Out]

1/5*c*d^3*x^5 + a*d^3*x + 1/77*(7*c*x^11 + 11*a*x^7)*e^3 + 1/15*(5*c*d*x^9 + 9*a*d*x^5)*e^2 + 1/7*(3*c*d^2*x^7
 + 7*a*d^2*x^3)*e

________________________________________________________________________________________

Sympy [A]
time = 0.01, size = 78, normalized size = 0.99 \begin {gather*} a d^{3} x + a d^{2} e x^{3} + \frac {c d e^{2} x^{9}}{3} + \frac {c e^{3} x^{11}}{11} + x^{7} \left (\frac {a e^{3}}{7} + \frac {3 c d^{2} e}{7}\right ) + x^{5} \cdot \left (\frac {3 a d e^{2}}{5} + \frac {c d^{3}}{5}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x**2+d)**3*(c*x**4+a),x)

[Out]

a*d**3*x + a*d**2*e*x**3 + c*d*e**2*x**9/3 + c*e**3*x**11/11 + x**7*(a*e**3/7 + 3*c*d**2*e/7) + x**5*(3*a*d*e*
*2/5 + c*d**3/5)

________________________________________________________________________________________

Giac [A]
time = 4.20, size = 71, normalized size = 0.90 \begin {gather*} \frac {1}{11} \, c x^{11} e^{3} + \frac {1}{3} \, c d x^{9} e^{2} + \frac {3}{7} \, c d^{2} x^{7} e + \frac {1}{5} \, c d^{3} x^{5} + \frac {1}{7} \, a x^{7} e^{3} + \frac {3}{5} \, a d x^{5} e^{2} + a d^{2} x^{3} e + a d^{3} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^3*(c*x^4+a),x, algorithm="giac")

[Out]

1/11*c*x^11*e^3 + 1/3*c*d*x^9*e^2 + 3/7*c*d^2*x^7*e + 1/5*c*d^3*x^5 + 1/7*a*x^7*e^3 + 3/5*a*d*x^5*e^2 + a*d^2*
x^3*e + a*d^3*x

________________________________________________________________________________________

Mupad [B]
time = 0.03, size = 71, normalized size = 0.90 \begin {gather*} x^5\,\left (\frac {c\,d^3}{5}+\frac {3\,a\,d\,e^2}{5}\right )+x^7\,\left (\frac {3\,c\,d^2\,e}{7}+\frac {a\,e^3}{7}\right )+\frac {c\,e^3\,x^{11}}{11}+a\,d^3\,x+a\,d^2\,e\,x^3+\frac {c\,d\,e^2\,x^9}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + c*x^4)*(d + e*x^2)^3,x)

[Out]

x^5*((c*d^3)/5 + (3*a*d*e^2)/5) + x^7*((a*e^3)/7 + (3*c*d^2*e)/7) + (c*e^3*x^11)/11 + a*d^3*x + a*d^2*e*x^3 +
(c*d*e^2*x^9)/3

________________________________________________________________________________________